Krzyś' measurement growing post

Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. (10 Marks)

The Pythagorean Theorem is a theory that was created and explained by the great mathmatician Pythagoras. Once you Learn it the theory is really quite simple. The Theory is:
"a" squared + "b" squared = "c" squared. You can examine how to solve for the hypotenuse (which is always c) by viewing the bubbleshare below:
place the "a", "b", and "c" in the equation with the appropriate numbers that correspond to the numbers given to you in the diagram.
If you would like to see how to solve for a missing leg, then please see the bubbleshare below:

Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.(10 Marks)

A Rectangular Prism is a Polyhedron. That means that it is a 3 dimensional shape and the different faces of it are polygons put together. Here are some examples of Rectangular Prisms:

To find the surface area of a right rectangular Prism, you must basically find the surface area of the different sides and then add them all together. The Formula for doing this is: sa=2(lxw)+2(lxd)+2(wxd). Or you could say: suface area = 2(length x width) + 2(length x depth) + 2(width x depth). To see how to solve for the surface area of a rectangular prism in more detail see the diagram below.

Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples. (10 Marks)
A right cylinder is simply a tube with two circle ends on it. Examples can be see underneath::
Below is an example of a cylinder and it's net and how to find the surface area:

Qestion 4: What is a polygon and how do we classify one? (10 Marks)

A polygon is an enclosed shape that has no bends, only straight lines. A Regular polygon is a polygon that has all the same angles and lengths. An irregular polygon would be a polygon that has as little as one length or angle not the same as all the others.

All of the shapes in this picture are Polygons. (exept the Snake head of course)

Here are some more Polygons from the producers of Gliffy!!

Michelle's Measurement Growing Post

Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples.

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Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.

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Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples.

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Question 4: What is a polygon and how do we classify one?

Amrit's Measurement Growing Post

Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. (10 Marks)
Pythagorean Theorem is way to figure out the lenght for the hypotenuse (c). The first step is a squared + b squared =c squared. The next step is to put in the value for a squared and b squared. Then you find the value for the squared letters. After that you add them together and find the square root. center;width:280px;display:block;">

This album is powered by BubbleShare - Add to my blog'>http://www.macromedia.com/go/getflashplayer" quality="high" src
Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.(10 Marks)
The formula to find the surface area of a rectangular prism is 2(l x h)+ 2(h x w)+ 2(l x w). The reason we multiply by two, is because there are two lenghts, two heights, and two widths.

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Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples. (10 Marks)

A right cylinder is a three dimensional figure that has parallel lines (height) with circles for bases that are congruent.

The formula for finding the surface area is 2(πr2+π rh).

SA= 2(3.14)10squared + (3.14)(10)(30)

SA= 6.28 (100)+(6.28)(300)

SA=25.12

Question 4: What is a polygon and how do we classify one? (10 Marks)
A polygon is a closed 2 dimensional figure that has atleast 3 straight lines. An irregular polygon is one that has different side lengths or angles. A regular polygon is a polygon that has all of the sides the same length, and all of the same angles.

To make the pictures more clear, just click on them and should open up bigger.

Jeff's Measurement Growing Post

Question 1: What is the Pythagorean Theorem?

The Pythagorean Thereom states that the square of the hypotenuse is equal to the square of the altitude and base combined.

Question 2: How do you find the surface area of a right rectangular prism?
The formula for finding the surface area of a right rectangular prism is:

SA = 2(l x w) + 2(l x h) + 2(w x h)

Question 3: How do you find the surface area of a right cylinder?

To find the surface area of a right cylinder we must first understand what a right cylinder is. A right cylider is a 3 dimensional object that has two identical ends (also called a top and bottom) that are circles and have one curved side that stretches around the circumfrance of the ends.

This is a right cylinder net.

These are cylinders.

The formula for finding the surface area of

a cylinder is this:

2 (3.14) x r x r + 2(3.14) x r x h

In the diagram to the left the formula would be:

SA = 2(3.14) x (2 x 2) + 2(3.14) x 2 x 5
SA = 6.28 x 4 + 6.28 x 2 x 5
SA = 39.44 + 62.8

SA = 102.24 cm square

Question 4: What is a polygon and how do we classify one?
These are some examples of Polygons

Polygons are enclosed shapes that has 3 or more sides.




















Irregular Polygons: Irregular polygons can have sides with different lengths. They can also have different sized angles.

Regular Polygons: All angles are the same and the lenghts of the sides are all the same.






If you would like to know more about polygons go to this website http://www.kidsnewsroom.org/elmer/infocentral/geometry/OtherPolygons.html

Kyla's Measurement Growing Post

Question #1: What is the pythagorean Theorem? You
should use words, pictures, symbols, and
numerical examples.

The Pythagorean Therom is named after the Greek matematician Pythagoras. The therom is:
All right angle triangles are labeled the same way. The side opposit the right angle is called the Hypotenuse and is always labelled "C". The second side is called the Altitude, which is labeled "A", and the Base is labeled "B".

Here is how you find the Hypotenuse of a right triangle (or the C side):

A2 + B2 = C2 (Write out the formula)

242 + 332 = C2 (plug the numbers in)

576 + 1089 = C2 (find out what it equles)

1665= C2 (add the numbers together)

square root of 1665= square root of C2

40.80cm= C (your answer)

Here is how to find the Altitude of the right triangle:

A2 + B2 = C2(write out the formula)

A2 + 142 = 172 (insert the numbers in)

A2 + 198 = 289 (find out what they equle)

A2= 289 - 198 (icolate the variable)

A2= 91 (subtract)

square root of A2 = square root of 91

A= 9.54 m (final answer)

Question #2: How do you find the surface area of a right
rectangular prism? You should use words, pictures,
symbols, and numerical examples.

To find the surface area of a right rectangle prism you simply do this formula:

SA = 2 (L x H) + 2 (H x W) + 2 (W x L)

L= length, W= width and H=height

Still don't understand? Here is an example:

The lengh of this right rectangular prism is 7m. The Width of this right rectangular prism is 3m and the Height of this right rectangular prism is 4m. If you are trying to solve this problem, here are the steps you should write:

SA= 2 (L x H) + 2 (H x W) + (W x L) (re write the formula)

SA= 2 (7 x 4) + 2 (4 x 3) + 2 (3 x 7) (insert the correct numbers)

SA= 2 (28) + 2 (12) + 2 (21) (find out what the product of the numbers in brackets is)

SA= 56 + 24 + 42 ( 2 x the number in brackets)

SA= 122 m2 (add the numbers up for the answer)

A right rectangular prism is a prism where the joining edges and faces are perpinduclar to the base faces.

Examples of rectangular prisms:

This is a filing cabinet

This is a TV

Question #3: How do you find the surface area of a right
cylinder? You should use words, pictures, symbols,
and numerical examples.

A right cylinder is a three-dimensional figure made up of the set of line segments parallel to a line through the 2 parallel planes and joining congruent curcular bases in the 2 planes. Here are some examples of cylinders in real life:

This is a can of tomato soup

This is a can of coke

This is a right cylinder net:

Here is how to find the surface area of a cylander:

SA= 2πr2 + 2πrh (write the formula for finding the surface area of a cylinder)

SA= 2 (3.14) (72) + 2(3.14) (7) (13) (insert the numbers from the cylinder)

SA= 2 (3.14) (49) + 2 (3.14) (91) (multiply the numbers)

SA= 6.28 (40) + 6.28 (91) (finish multiplying the numbers)

SA= 251.2 + 571. 48 (add the numbers together)

SA= 822.68 m2 (get your answer)

Question 4: What is a polygon and how do we classify one?

A polygon is a closed figure that has at least three sides. The lines that make up the polygon must be strait lines. There are two types of polygons: "Regular Polygons" and "Irregular Polygons". A regular polygon is where all sides are congruent and all interior angles are also congruent. Congurent means that they all are the same shape and size. A irregualr polygon is the oposit, the sides and angles are all not the same shape and size.

Lauren's Measurement Growing Post

Question #1: What is the Pythagorean Theorem? You
should use words, pictures, symbols, and
numerical examples. (10 marks)

The Pythagorean theorem was discovered by Pythagoras in Enchant Greece. He discovered that the altitude and base squared on a right triangle added together will equal the hypotenuse squared. This will work for any right triangle. All you have to do is follow this formula and full in the measurements.

As you can see in this diagram if you multiply 12 by 12 you'll get 144. Then if you multiply 35 by 35 you'll get 1225. Then if you multiply 37 by 37 it should equal
144+ 1225 if it is a proper right angle.
so 37 x 37= 1369
144 + 1225 = 1369

So this proves you can find if a triangle is right or not.
But then you think to your self what if another number is missing that isn't the hypotenuse? Well that is easy all you have to do is use algebra. For instance if the 12 was missing in the diagram above you would just fill in the formula( )
so it would be......

Question #2: How do you find the surface area of a right
rectangular prism? You should use words, pictures,
symbols, and numerical examples. (10 marks)

The definition of a rectangular prism is it has 6 sides, it is made up of right angles, and the lines are straight.
These are many examples of rectangular prisms.

Many every day objects are rectangular prisms....

Just like this Mini wheats cereal box :)

To find a rectangles surface area all you need is a simple formula.
2(l . W) + 2(l . H) + 2(W . H) = surface area of a rectangular prism.
We were discussing in class where this formula came from. The "L" stands for length, the "W" stands for width, and the "H" stands for height but you can also use "D" instead which stands for depth.

So If you think about a rectangular prism there are 2 of each side. There is a front and a back which are the same. There is 2 sides and there is a top and a bottom which are the same. So if you look at the image above you can think out the formula. The surface area is finding the area of the outside not the inside. So really you're just finding the area of each side and adding them together.

If you look at the front side to find the area would be L times H. To find the side it would be W times H. and to find the top it would be L times W. So that explains the formula. So then you just fill in the measurements and work it out.

Question #3: How do you find the surface area of a right
cylinder? You should use words, pictures, symbols,
and numerical examples. (10 marks)

Okay everyone now lets not panic. If you think about it a right cylinder is only a rectangle and 2 circles put together. So the definition is it has to have 2 circles on either end and they have to be attached by a rectangle made into a round tube.


So in this diagram you can see a cylinder's net and the folded up version of the same shape.

So to find the Surface area (S.A) of a right cylinder you have to follow a simple formula....Well mayby not that simple but just don't panic :)

r=radius Pi=3.14 h=height

So if the the radius was 3 cm and the height was 21cm what would the S.A be? lets work it out...

and that's how you find the surface area of a right cylinder. But if in a question they only give you the diameter and height just divide the diameter by 2 to get the radious then solve it just the same:)

Here are some more examples of cylinders....

The pillsbury doughboy couldn't live without cylinders...He wouldn't be able to package up his delicious cinnamon rolls! not to mention turnovers :)

And don't forget for when you're sick! everyone has a can soup. But to think if you didn't have cylinders there wouldn't be chicken noodle soup!!! With vegetables! How would you servive!

Question #4: What is a polygon and how do we
classify one? (10 marks)

A Polygon is a closed figure with straight sides.

A Regular Polygon: This is a polygon that has all
sides equal and all angles the same.

An Irregular Polygon: This type of polygon has sides different lengths. They can be all different lengths or they can have some the same. An irregular polygon also has different angles.


This is an example of a 20 sided polygon. As long as the sides are straight and the figure is closed it will end up becoming a polygon.

Lookin' for the posts for this week!

Hey guys - WHERE ARE THE POSTS FOR THIS WEEK? MS, let's get it going!

Solving type 4 algebra March 22, 2007

first, move all of the variables to one side and add/subtract them

so it looks like this on the left.

Then solve the problem like any other algebra problem.

The next blogger is

MS

March 22 Math Class

In classes earlier in march we have been learning type one and type 2 equations in algebra. Today we learned that we would be doing type 3 and type four equations.
All we have to add is one or two steps.
Type two equations are pretty much the same except you have to undo more steps.
Here is an example...



Most people havn't seen the variable in brackets before but don't PANIC it's easy. Since there is multiplication out side of the brackets you have to times everything in the brackets by three. So then the brackets are gone and you now have a type 2 equation. Just make sure to watch the negatives and positives. Oh and don't forget to check your answer!












So now here you see anouther type three equation. As you can see there is a fraction in brackets. Scary i know but just go step by step. First you have to multiply everything in the brackets by four. So them that gets rid of the brackets. Then you just have to work it out normally like a type two equation.







and the new blogger is.....

EB!!!

Type II Equations

Today in class we continued our work with type II algebra equations.
Type II equations require two steps to solve.

Below is one example of a type II equation.
As you can see subtraction was used then multiplication.

Next blogger is LN

Type one and type two equations

In class on last Friday, we learned how to solve type two equations. With type two equations, it takes two steps to solve.We had an assignment from the text book with both type one and two equations.
Ex.1) 4a+2=-2
Step 1 4a=-2-2
step 2 4a/4=-4/4
answer a=-1
For more information on algebra check the folling site: http://www.mathleague.com/help/algebra/algebra.htm
The next blogger is JW

type one problems/ math class today (March 15)

In math class today, we did'nt really learn much. All we did was work on a homework booklet that was given yesterday. The booklet is basically a practise sheet for type 1 math problems Ex.x + 9 = 17
x = 17 - 9
x = 8

Scribe post for March 14th

In class we learned how to do Type I Equations. This is the most basic kind of algebra equation. Here are a few examples.

This is a summary of the work we did in class today. Here are a few heplful links yu can use to help you on these questions.
http://www.coolmath.com/algebra/Algebra1/03SolveEquations/02_whattodo1.htm
http://www.coolmath.com/algebra/Algebra1/03SolveEquations/03_whattodo2.htm
Just copy and paste these links into your browser.